1 Introduction

Let H be a real Hilbert space with inner product , and induced norm . Let C be a nonempty closed convex subset of H and let T:CC be a self-map** on C. We denote by Fix(T) the set of fixed points of T.

We recall that a map** T:CH is said to be k-strictly pseudocontractive if there exists a constant k[0,1) such that

T x T y 2 x y 2 +k ( I T ) x ( I T ) y 2 ,x,yC.

The map** T is pseudocontractive if and only if

TxTy,xy x y 2 ,x,yC.

T is strongly pseudocontractive if and only if there exists a constant λ(0,1) such that

TxTy,xy(1λ) x y 2 ,x,yC.

Note that the class of k-strictly pseudocontractive map**s includes the class of nonexpansive map**s T on C (i.e., TxTyxy, x,yC) as a subclass. That is, T is nonexpansive if and only if T is 0-strictly pseudocontractive. The map** T is also said to be pseudocontractive if k=1 and T is said to be strongly pseudocontractive if there exists a positive constant λ(0,1) such that TλI is pseudocontractive. Clearly, the class of k-strictly pseudocontractive map**s falls into the one between classes of nonexpansive map**s and pseudocontractive map**s. Also we remark that the class of strongly pseudocontractive map**s is independent of the class of k-strictly pseudocontractive map**s (see [13]). The class of pseudocontractive map**s is one of the most important classes of map**s among nonlinear map**s. Recently, many authors have been devoting the studies on the problems of finding fixed points for pseudocontractive map**s; see, for example, [49] and the references therein.

Let A be a strongly positive bounded linear operator on H. That is, there is a constant γ ¯ >0 with the property

Ax,x γ ¯ x 2 ,xH.

It is well known that iterative methods for nonexpansive map**s can be used to solve a convex minimization problem: see, e.g., [1012] and the references therein. A typical problem is that of minimizing a quadratic function over the set of fixed points of a nonexpansive map** on a real Hilbert space H:

min x C 1 2 Ax,xx,b,
(1.1)

where C is the fixed point set of a nonexpansive map** S on H and b is a given point in H. In [11], Xu proved that the sequence { x n } generated by the iterative method for a nonexpansive map** S presented below with the initial guess x 0 H chosen arbitrary:

x n + 1 = α n b+(I α n A)S x n ,n0,
(1.2)

converges strongly to the unique solution of the minimization problem (1.1) provided the sequence { α n } satisfies certain conditions.

In [13], combining the Moudafi viscosity approximation method [14] with Xu’s method (1.2), Marino and Xu [13] considered the following general iterative method for a nonexpansive map** S:

x n + 1 = α n γf x n +(I α n A)S x n ,n0,
(1.3)

where f is a contractive map** on H with a constant α(0,1) (i.e., there exists a constant α(0,1) such that f(x)f(y)αxy, x,yH). They proved that if the sequence { α n } of control parameters satisfies appropriate conditions, then the sequence { x n } generated by (1.3) converges strongly to the unique solution of the variational inequality

( γ f A ) x ˜ , x x ˜ 0,xFix(S),

which is the optimality condition for the minimization problem

min x Fix ( S ) 1 2 Ax,xh(x),

where h is a potential function for γf (i.e., h =γf).

On the other hand, Yamada [12] introduced the following hybrid steepest-descent method for a nonexpansive map** S for solving the variational inequality:

x n + 1 =(I ξ n μF)S x n ,n0,
(1.4)

where S:HH is a nonexpansive map** with Fix(S); F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0 (i.e., FxFyρxy and FxFy,xyη x y 2 , x,yH, respectively), and 0<μ< 2 η ρ 2 , and then proved that if { ξ n } satisfies appropriate conditions, the sequence { x n } generated by (1.4) converges strongly to the unique solution of the variational inequality:

F x ˜ ,x x ˜ 0,xFix(S).

In 2010, by combining Yamada’s hybrid steepest-descent method (1.4) with Marino with Xu’s method (1.3), Tian [15] introduced the following general iterative method for a nonexpansive map** S:

x n + 1 = α n γf x n +(I α n μF)S x n ,n0,
(1.5)

where f is a contractive map** on H with a constant α(0,1). His results improved and complemented the corresponding results of Marino and Xu [13]. In [16], Tian also considered the following general iterative method for a nonexpansive map** S:

x n + 1 = α n γV x n +(I α n μF)S x n ,n0,
(1.6)

where V:HH is a Lipschitzian map** with a constant l0. In particular, the results in [16] extended the results of Tian [15] from the case of the contractive map** f to the case of a Lipschitzian map** V.

In 2011, Ceng et al. [17] also introduced the following iterative method for the nonexpansive map** S:

x n + 1 = P C [ α n γ V x n + ( I α n μ F ) S x n ] ,n0,
(1.7)

where F:CH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0, V:CH is an l-Lipschitzian map** with a constant l0 and 0<μ< 2 η ρ 2 . In particular, by using appropriate control conditions on { α n }, they proved that the sequence { x n } generated by (1.7) converges strongly to a fixed point x ˜ of S, which is the unique solution of the following variational inequality related to the operator F:

μF x ˜ γV x ˜ , x ˜ p0,pFix(S).

Their results also improved the results of Tian [15] from the case of the contractive map** f to the case of a Lipschitzian map** V.

In 2011, Ceng et al. [18] introduced the following general composite iterative method for a nonexpansive map** S:

{ y n = ( I α n μ F ) S x n + α n γ f x n , x n + 1 = ( I β n A ) S x n + β n y n , n 0 ,
(1.8)

which combines Xu’s method (1.2) with Tian’s method (1.5). Under appropriate control conditions on { α n } and { β n }, they proved that the sequence { x n } generated by (1.8) converges strongly to a fixed point x ˜ of S, which is the unique solution of the following variational inequality related to the operator A:

( A I ) x ˜ , x ˜ p 0,pFix(S).

Their results supplemented and developed the corresponding ones of Marino and Xu [13], Yamada [12] and Tian [15].

On the another hand, in 2011, by combining Yamada’s hybrid steepest-descent method (1.4) with Marino and Xu’s method (1.3), Jung [7] considered the following explicit iterative scheme for finding fixed points of a k-strictly pseudocontractive map** T for some 0k<1:

x n + 1 = α n γf( x n )+ β n x n + ( ( 1 β n ) I α n μ F ) P C S x n ,n0,
(1.9)

where S:CH is a map** defined by Sx=kx+(1k)Tx; P C is the metric projection of H onto C; f:CC is a contractive map** with a constant α(0,1); F:CC is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0; and 0<μ< 2 η ρ 2 . Under suitable control conditions on { α n } and { β n }, he proved that the sequence { x n } generated by (1.9) converges strongly to a fixed point x ˜ of T, which is the unique solution of the following variational inequality related to the operator F:

μF x ˜ γf x ˜ , x ˜ p0,pFix(T).

His result also improved and complemented the corresponding results of Cho et al. [5], Jung [6], Marino and Xu [13] and Tian [15].

In this paper, motivated and inspired by the above-mentioned results, we will combine Xu’s method (1.2) with Tian’s method (1.6) for a k-strictly pseudocontractive map** T for some 0k<1 and consider the following new general composite iterative method for finding an element of Fix(T):

{ y n = α n γ V x n + ( I α n μ F ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 ,
(1.10)

where T n :HH is a map** defined by T n x= λ n x+(1 λ n )Tx for 0k λ n λ<1 and lim n λ n =λ; A is a strongly positive bounded linear operator on H with a constant γ ¯ (1,2); { α n }[0,1] and { β n }(0,1] satisfy appropriate conditions; V:HH is a Lipschitzian map** with a constant l0; F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0; and 0<μ< 2 η ρ 2 . By using weaker control conditions than previous ones, we establish the strong convergence of the sequence generated by the proposed iterative method (1.10) to a point x ˜ in Fix(T), which is the unique solution of the variational inequality related to A:

( A I ) x ˜ , x ˜ p 0,pFix(T).

Our results complement, develop, and improve upon the corresponding ones given by Cho et al. [5] and Jung [68] for the strictly pseudocontractive map** as well as Yamada [12], Marino and Xu [13], Tian [15] and Ceng et al. [17] and Ceng et al. [18] for the nonexpansive map**.

2 Preliminaries and lemmas

Throughout this paper, when { x n } is a sequence in H, x n x (resp., x n x) will denote strong (resp., weak) convergence of the sequence { x n } to x.

For every point xH, there exists a unique nearest point in C, denoted by P C (x), such that

x P C ( x ) xy,yC.

P C is called the metric projection of H to C. It is well known that P C is nonexpansive and that, for xH,

z= P C xxz,yz0,yC.
(2.1)

In a Hilbert space H, we have

x y 2 = x 2 + y 2 2x,y,x,yH.
(2.2)

Lemma 2.1 In a real Hilbert space H, the following inequality holds:

x + y 2 x 2 +2y,x+y,x,yH.

Let LIM be a Banach limit. According to time and circumstances, we use LIM n ( a n ) instead of LIM(a) for every a={ a n } . The following properties are well known:

  1. (i)

    for all n1, a n c n implies LIM n ( a n ) LIM n ( c n ),

  2. (ii)

    LIM n ( a n + N )= LIM n ( a n ) for any fixed positive integer N,

  3. (iii)

    lim inf n a n LIM n ( a n ) lim sup n a n for all { a n } l .

The following lemma was given in [[19], Proposition 2].

Lemma 2.2 Let aR be a real number and let a sequence { a n } l satisfy the condition LIM n ( a n )a for all Banach limit LIM. If lim sup n ( a n + 1 a n )0, then lim sup n a n a.

We also need the following lemmas for the proof of our main results.

Lemma 2.3 ([20, 21])

Let { s n } be a sequence of non-negative real numbers satisfying

s n + 1 (1 ω n ) s n + ω n δ n + r n ,n0,

where { ω n }, { δ n }, and { r n } satisfy the following conditions:

  1. (i)

    { ω n }[0,1] and n = 0 ω n =,

  2. (ii)

    lim sup n δ n 0 or n = 0 ω n | δ n |<,

  3. (iii)

    r n 0 (n0), n = 0 r n <.

Then lim n s n =0.

Lemma 2.4 ([22] Demiclosedness principle)

Let C be a nonempty closed convex subset of a real Hilbert space H, and let S:CC be a nonexpansive map**. Then the map** IS is demiclosed. That is, if { x n } is a sequence in C such that x n x and (IS) x n y, then (IS) x =y.

Lemma 2.5 ([23])

Let H be a real Hilbert space and let C be a closed convex subset of H. Let T:CH be a k-strictly pseudocontractive map** on C. Then the following hold:

  1. (i)

    The fixed point set Fix(T) is closed convex, so that the projection P Fix ( T ) is well defined.

  2. (ii)

    Fix( P C T)=Fix(T).

  3. (iii)

    If we define a map** S:CH by Sx=λx+(1λ)Tx for all xC. then, as λ[k,1), S is a nonexpansive map** such that Fix(T)=Fix(S).

The following lemma can easily be proven (see also [12]).

Lemma 2.6 Let H be a real Hilbert space H. Let F:HH be a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0. Let 0<μ< 2 η ρ 2 and 0<t<ξ1. Then G:=ξItμF:HH is a contractive map** with constant ξtτ, where τ=1 1 μ ( 2 η μ ρ 2 ) .

Lemma 2.7 ([13])

Assume that A is a strongly positive bounded linear operator on H with a coefficient γ ¯ >0 and 0<ζ A 1 . Then IζA1ζ γ ¯ .

Finally, we recall that the sequence { x n } in H is said to be weakly asymptotically regular if

w- lim n ( x n + 1 x n )=0,that is,  x n + 1 x n 0

and asymptotically regular if

lim n x n + 1 x n =0,

respectively.

3 The main results

Throughout the rest of this paper, we always assume the following:

  • H is a real Hilbert space;

  • T:HH is a k-strictly pseudocontractive map** with Fix(T) for some 0k<1;

  • F:HH is a ρ-Lipschitzian and η-strongly monotone operator with constants ρ>0 and η>0;

  • A:HH is a strongly positive linear bounded operator on H with a constant γ ¯ (1,2);

  • V:HH is an l-Lipschitzian map** with a constant l0;

  • 0<μ< 2 η ρ 2 and 0γl<τ, where τ=1 1 μ ( 2 η μ ρ 2 ) ;

  • T t :HH is a map** defined by T t x= λ t x+(1 λ t )Tx, t(0,1), for 0k λ t λ<1 and lim t 0 λ t =λ;

  • T n :HH is a map** defined by T n x= λ n x+(1 λ n )Tx for 0k λ n λ<1 and lim n λ n =λ;

  • P Fix ( T ) is a metric projection of H onto Fix(T).

By Lemma 2.5(iii), we note that T t and T n are nonexpansive and Fix(T)=Fix( T t )=Fix( T n ).

In this section, we introduce the following general composite scheme that generates a net { x t } t ( 0 , min { 1 , 2 γ ¯ τ γ l } ) in an implicit way:

x t =(I θ t A) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] .
(3.1)

We prove strong convergence of { x t } as t0 to a fixed point x ˜ of T which is a solution of the following variational inequality:

( A I ) x ˜ , x ˜ p 0,pFix(T).
(3.2)

We also propose the following general composite explicit scheme, which generates a sequence in an explicit way:

{ y n = α n γ V x n + ( I α n μ F ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 ,
(3.3)

where { α n }[0,1], { β n }(0,1] and x 0 H is an arbitrary initial guess, and establish strong convergence of this sequence to a fixed point x ˜ of T, which is also the unique solution of the variational inequality (3.2).

Now, for t(0,min{1, 2 γ ¯ τ γ l }) and θ t (0, A 1 ], consider a map** Q t :HH defined by

Q t x=(I θ t A) T t x+ θ t [ t γ V x + ( I t μ F ) T t x ] ,xH.

It is easy to see that Q t is a contractive map** with constant 1 θ t ( γ ¯ 1+t(τγl)). Indeed, by Lemma 2.6 and Lemma 2.7, we have

Q t x Q t y ( I θ t A ) T t x ( I θ t A ) T t y + θ t [ t γ V x + ( I t μ F ) T t x ] [ t γ V y + ( I t μ F ) T t y ] ( 1 θ t γ ¯ ) x y + θ t [ t γ V x V y + ( I t μ F ) T t x ( I t μ F ) T t y ] ( 1 θ t γ ¯ ) x y + θ t ( 1 t ( τ γ l ) ) x y = [ 1 θ t ( γ ¯ 1 + t ( τ γ l ) ) ] x y .

Since γ ¯ (1,2), τγl>0, and

0<t<min { 1 , 2 γ ¯ τ γ l } 2 γ ¯ τ γ l ,

it follows that

0< ( γ ¯ 1 + t ( τ γ l ) ) <1,

which along with 0< θ t A 1 <1 yields

0<1 θ t ( γ ¯ 1 + t ( τ γ l ) ) <1.

Hence Q t is a contractive map**. By the Banach contraction principle, Q t has a unique fixed point, denoted x t , which uniquely solves the fixed point equation (3.1).

We summary the basic properties of { x t }, which can be proved by the same method in [18]. We include its proof for the sake of completeness.

Proposition 3.1 Let { x t } be defined via (3.1). Then

  1. (i)

    { x t } is bounded for t(0,min{1, 2 γ ¯ τ γ l });

  2. (ii)

    lim t 0 x t T t x t =0 provided lim t 0 θ t =0;

  3. (iii)

    x t :(0,min{1, 2 γ ¯ τ γ l })H is locally Lipschitzian provided θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is locally Lipschitzian, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is locally Lipschitzian;

  4. (iv)

    x t defines a continuous path from (0,min{1, 2 γ ¯ τ γ l }) into H provided θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is continuous, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is continuous.

Proof (1) Let pFix(T). Observing Fix(T)=Fix( T t ) by Lemma 2.5(iii), we have

x t p = ( I θ t A ) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t [ t γ V x t + ( I t μ F ) T t x t p ] + θ t ( I A ) p ( I θ t A ) T t x t ( I θ t A ) T t p + θ t t γ V x t + ( I t μ F ) T t x t p + θ t ( I A ) p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t ( I t μ F ) T t x t ( I t μ F ) T t p + t ( γ V x t μ F p ) + θ t I A p ( 1 θ t γ ¯ ) x t p + θ t [ ( 1 t τ ) x t p + t ( γ l x t p + γ V p μ F p ) ] + θ t I A p .

So, it follows that

x t p I A p + t γ V p μ F p γ ¯ 1 + t ( τ γ l ) I A p + t γ V p μ F p γ ¯ 1 I A p + γ V p μ F p γ ¯ 1 .

Hence { x t } is bounded and so are {V x t }, {T x t }, { T t x t }, and {F T t x t }.

(ii) By the definition of { x t }, we have

x t T t x t = θ t [ ( I A ) T t x t + t ( γ V x t μ F T t x t ) ] = θ t ( I A ) T t x t + t ( γ V x t μ F T t x t ) θ t I A T t x t + t γ V x t μ F T t x t 0 as  t 0 ,

by the boundedness of {V x t } and {F T t x t } in (i).

  1. (iii)

    Let t, t 0 (0,min{1, 2 γ ¯ τ γ l }), Noting that

    T t x t T t 0 x t 0 T t x t T t x t 0 + T t x t 0 T t 0 x t 0 x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ,

we calculate

x t x t 0 = ( I θ t A ) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] ( I θ t 0 A ) T t 0 x t 0 θ t 0 [ t 0 γ V x t 0 + ( I t 0 μ F ) T t 0 x t 0 ] ( I θ t A ) T t x t ( I θ t 0 A ) T t x t + ( I θ t 0 A ) T t x t ( I θ t 0 A ) T t 0 x t 0 + | θ t θ t 0 | t γ V x t + ( I t μ F ) T t x t + θ t 0 [ t γ V x t + ( I t μ F ) T t x t ] [ t 0 γ V x t 0 + ( I t 0 μ F ) T t 0 x t 0 ] | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) T t x t T t 0 x t 0 + | θ t θ t 0 | t γ V x t + ( I t μ F ) T t x t + θ t 0 ( t t 0 ) γ V x t + t 0 γ ( V x t V x t 0 ) ( t t 0 ) μ F T t x t + ( I t 0 μ F ) T t x t ( I t 0 μ F ) T t 0 x t 0 | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) [ x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ] + | θ t θ t 0 | [ T t x t + t ( γ V x t + μ F T t x t ) ] + θ t 0 [ ( γ V x t + μ F T t x t ) | t t 0 | + t 0 γ l x t x t 0 + ( 1 t 0 τ ) T t x t T t 0 x t 0 ] | θ t θ t 0 | A T t x t + ( 1 θ t 0 γ ¯ ) ( x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ) + | θ t θ t 0 | ( T t x t + γ V x t + μ F T t x t ) + θ t 0 ( γ V x t + μ F T t x t ) | t t 0 | + θ t 0 t 0 γ l x t x t 0 + θ t 0 ( 1 t 0 τ ) ( x t x t 0 + | λ t λ t 0 | x t 0 T x t 0 ) .

This implies that

x t x t 0 A T t x t + T t x t + γ V x t + μ F T t x t θ t 0 ( γ ¯ 1 + t 0 ( τ γ l ) ) | θ t θ t 0 | + γ V x t + μ F T t x t γ ¯ 1 + t 0 ( τ γ l ) | t t 0 | + [ 1 θ t 0 ( γ ¯ 1 + t 0 τ ) ] x t 0 T x t 0 θ t 0 ( γ ¯ 1 + t 0 ( τ γ l ) ) | λ t λ t 0 | .

Since θ t :(0,min{1, 2 γ ¯ τ γ l })(0, A 1 ] is locally Lipschitzian, and λ t :(0,min{1, 2 γ ¯ τ γ l })[k,λ] is locally Lipschitzian, x t is also locally Lipschitzian.

  1. (iv)

    From the last inequality in (iii), the result follows immediately. □

We prove the following theorem for strong convergence of the net { x t } as t0, which guarantees the existence of solutions of the variational inequality (3.2).

Theorem 3.1 Let the net { x t } be defined via (3.1). If lim t 0 θ t =0, then x t converges strongly to a fixed point x ˜ of T as t0, which solves the variational inequality (3.2). Equivalently, we have P Fix ( T ) (2IA) x ˜ = x ˜ .

Proof We first show the uniqueness of a solution of the variational inequality (3.2), which is indeed a consequence of the strong monotonicity of AI. In fact, since A is a strongly positive bounded linear operator with a coefficient γ ¯ (1,2), we know that AI is strongly monotone with a coefficient γ ¯ 1(0,1). Suppose that x ˜ Fix(T) and x ˆ Fix(T) both are solutions to (3.2). Then we have

( A I ) x ˜ , x ˜ x ˆ 0
(3.4)

and

( A I ) x ˆ , x ˆ x ˜ 0.
(3.5)

Adding up (3.4) and (3.5) yields

( A I ) x ˜ ( A I ) x ˆ , x ˜ x ˆ 0.

The strong monotonicity of AI implies that x ˜ = x ˆ and the uniqueness is proved.

Next, we prove that x t x ˜ as t0. Observing Fix(T)=Fix( T t ) by Lemma 2.5(iii), from (3.1), we write, for given pFix(T),

x t p = ( I θ t A ) T t x t ( I θ t A ) T t p + θ t [ t γ V x t + ( I t μ F ) T t x t p ] + θ t ( I A ) p = ( I θ t A ) ( T t x t T t p ) + θ t [ t ( γ V x t μ F p ) + ( I t μ F ) T t x t ( I t μ F ) p ] + θ t ( I A ) p ,

to derive

x t p 2 = ( I θ t A ) ( T t x t T t p ) , x t p + θ t [ t γ V x t μ F p , x t p + ( I t μ F ) T t x t ( I t μ F ) p , x t p ] + θ t ( I A ) p , x t p ( 1 θ t γ ¯ ) x t p 2 + θ t [ ( 1 t τ ) x t p 2 + t γ l x t p 2 + t γ V p μ F p , x t p ] + θ t ( I A ) p , x t p = [ 1 θ t ( γ ¯ 1 + t ( τ γ l ) ) ] x t p 2 + θ t ( t γ V p μ F p , x t p + ( I A ) p , x t p ) .

Therefore,

x t p 2 1 γ ¯ 1 + t ( τ γ l ) ( t γ V p μ F p , x t p + ( I A ) p , x t p ) .
(3.6)

Since { x t } is bounded as t0 (by Proposition 3.1(i)), we see that if { t n } is a subsequence in (0,min{1, 2 γ ¯ τ γ l }) such that t n 0 and x t n x , then from (3.6), we obtain x t n x . We show that x Fix(T). To this end, define S:HH by Sx=λx+(1λ)Tx, xH, for 0kλ<1. Then S is nonexpansive with Fix(S)=Fix(T) by Lemma 2.5(iii). Noticing that

S x t n x t n S x t n T t n x t n + T t n x t n x t n = ( λ λ t n ) x t n T x t n + T t n x t n x t n = λ λ t n 1 λ t n x t n T t n x t n + T t n x t n x t n = 1 + λ 2 λ t n 1 λ t n x t n T t n x t n ,

by Proposition 3.1(ii) and λ t n λ as t n 0, we have lim n (IS) x t n =0. Thus it follows from Lemma 2.4 that x Fix(S). By Lemma 2.5(iii), we get x Fix(T).

Finally, we prove that x is a solution of the variational inequality (3.2). Since

x t =(I θ t A) T t x t + θ t [ t γ V x t + ( I t μ F ) T t x t ] ,

we have

x t T t x t = θ t (IA) T t x t + θ t t(γV x t μF T t x t ).

Since T t is nonexpansive, I T t is monotone. So, from the monotonicity of I T t , it follows that, for pFix(T)=Fix( T t ),

0 ( I T t ) x t ( I T t ) p , x t p = ( I T t ) x t , x t p = θ t ( I A ) T t x t , x t p + θ t t γ V x t μ F T t x t , x t p = θ t ( I A ) x t , x t p + θ t ( I A ) ( T t I ) x t , x t p + θ t t γ V x t μ F T t x t , x t p .

This implies that

( A I ) x t , x t p ( I A ) ( T t I ) x t , x t p +tγV x t μF T t x t , x t p.
(3.7)

Now, replacing t in (3.7) with t n and letting n, noticing the boundedness of {γV x t n μF T t n x t n } and the fact that (IA)( T t n I) x t n 0 as n by Proposition 3.1(ii), we obtain

( A I ) x , x p 0.

That is, x Fix(T) is a solution of the variational inequality (3.2); hence x = x ˜ by uniqueness. In summary, we have shown that each cluster point of { x t } (at t0) equals x ˜ . Therefore x t x ˜ as t0.

The variational inequality (3.2) can be rewritten as

( 2 I A ) x ˜ x ˜ , x ˜ p 0,pFix(T).

Recalling Lemma 2.5(i) and (2.1), this is equivalent to the fixed point equation

P Fix ( T ) (2IA) x ˜ )= x ˜ .

 □

Taking F=I, μ=1 and γ=1 in Theorem 3.1, we get

Corollary 3.1 Let { x t } be defined by

x t =(I θ t A) T t x t + θ t [ t V x t + ( 1 t ) T t x t ] .

If lim t 0 θ t =0, then { x t } converges strongly as t0 to a fixed point x ˜ of T, which is the unique solution of variational inequality (3.2).

First, we prove the following result in order to establish strong convergence of the sequence { x n } generated by the general composite explicit scheme (3.3).

Theorem 3.2 Let { x n } be the sequence generated by the explicit scheme (3.3), where { α n } and { β n } satisfy the following condition:

(C1) { α n }[0,1] and { β n }(0,1], α n 0 and β n 0 as n.

Let LIM be a Banach limit. Then

LIM n ( ( A I ) x ˜ , x ˜ x n ) 0,

where x ˜ = lim t 0 + x t with x t being defined by

x t =(I θ t A)S x t + θ t [ t γ V x t + ( I t μ F ) S x t ] ,
(3.8)

where S:HH is defined by Sx=λx+(1λ)Tx for 0kλ<1.

Proof First, note that from the condition (C1), without loss of generality, we assume that 0< β n A 1 for all n0.

Let { x t } be the net generated by (3.8). Since S is a nonexpansive map** on H, by Theorem 3.1 with T t =S and Lemma 2.5, there exists lim t 0 x t Fix(S)=Fix(T). Denote it by x ˜ . Moreover, x ˜ is the unique solution of the variational inequality (3.2). From Proposition 3.1(i) with T t =S, we know that { x t } is bounded, so are {V x t } and {FS x t }.

First of all, let us show that { x n } is bounded. To this end, take pFix(T)=Fix( T n ), Then it follows that

y n p = α n γ V x n + ( I α n μ F ) T n x n p = α n ( γ V x n μ F p ) + ( I α n μ F ) T n x n ( I α n μ F ) T n p ( 1 α n ( τ γ l ) ) x n p + α n γ V p μ F p ,

and hence

x n + 1 p = ( I β n A ) T n x n + β n y n p = ( I β n A ) T n x n ( I β n A ) T n p + β n ( y n p ) + β n ( I A ) p ( I β n A ) T n x n ( I β n A ) T n p + β n y n p + β n I A p ( 1 β n γ ¯ ) x n p + β n [ ( 1 α n ( τ γ l ) ) x n p + α n γ V p μ F p ] + β n I A p ( 1 β n ( γ ¯ 1 ) ) x n p + β n ( γ V p μ F p + I A p ) = ( 1 β n ( γ ¯ 1 ) ) x n p + β n ( γ ¯ 1 ) γ V p μ F p + I A p γ ¯ 1 max { x n p , γ V p μ F p + I A p γ ¯ 1 } .

By induction

x n pmax { x 0 p , γ V p μ F p + I A p γ ¯ 1 } ,n0.

This implies that { x n } is bounded and so are {T x n }, { T n x n }, {F T n x n }, {V x n }, and { y n }. As a consequence, with the control condition (C1), we get

x n + 1 T n x n = β n y n A T n x n 0(n),

and

S x t x n + 1 S x t S x n + S x n T n x n + T n x n x n + 1 x t x n + | λ λ n | x n T x n + T n x n x n + 1 = x t x n + e n ,
(3.9)

where e n =|λ λ n | x n T x n + x n + 1 T n x n 0 as n. Also observing that A is strongly positive, we have

A x t A x n , x t x n = A ( x t x n ) , x t x n γ ¯ x t x n 2 .
(3.10)

Now, by (3.8), we have

x t x n + 1 = ( I θ t A ) S x t + θ t [ t γ V x t + ( I t μ F ) S x t ] x n + 1 = ( I θ n A ) S x t ( I θ t A ) x n + 1 + θ t [ t γ V x t + ( I t μ F ) S x t A x n + 1 ] .

Applying Lemma 2.1, we have

x t x n + 1 2 ( I θ t A ) S x t ( I θ t A ) x n + 1 2 + 2 θ t S x t t ( μ F S x t γ V x t ) A x n + 1 , x t x n + 1 ( 1 θ t γ ¯ ) 2 S x t x n + 1 2 + 2 θ t S x t x t , x t x n + 1 2 θ t t μ F S x t γ V x t , x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 .
(3.11)

Using (3.9) and (3.10) in (3.11), we obtain

x t x n + 1 2 ( 1 θ t γ ¯ ) 2 S x t x n + 1 2 + 2 θ t S x t x t , x t x n + 1 + 2 θ t t γ V x t μ F S x t , x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 ( 1 θ t γ ¯ ) 2 ( x t x n + e n ) 2 + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 = ( θ t 2 γ ¯ 2 θ t ) γ ¯ x t x n 2 + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 ( θ t 2 γ ¯ 2 θ t ) A x t A x n , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t x t A x n + 1 , x t x n + 1 = θ t 2 γ ¯ A x t A x n , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F ( S x t ) x t x n + 1 + 2 θ t [ x t A x n + 1 , x t x n + 1 A x t A x n , x t x n ] = θ t 2 γ ¯ A ( x t x n ) , x t x n + x t x n 2 + ( 1 θ t γ ¯ ) 2 ( 2 x t x n e n + e n 2 ) + 2 θ t S x t x t x t x n + 1 + 2 θ t t γ V x t μ F S x t x t x n + 1 + 2 θ t [ ( I A ) x t , x t x n + 1 + A ( x t x n + 1 ) , x t x n + 1 A ( x t x n ) , x t x n ] .
(3.12)

Applying the Banach limit LIM to (3.12), together with lim n e n =0, we have

LIM n ( x t x n + 1 2 ) θ t 2 γ ¯ LIM n ( A ( x t x n ) , x t x n ) + LIM n ( x t x n 2 ) + 2 θ t S x t x t LIM n ( x t x n + 1 ) + 2 θ t t γ V x t μ F S x t LIM n ( x t x n + 1 ) + 2 θ t [ LIM n ( ( I A ) x t , x t x n + 1 ) + LIM n ( A ( x t x n + 1 ) , x t x n + 1 ) LIM n ( A ( x t x n ) , x t x n ) ] .
(3.13)

Using the property LIM n ( a n )= LIM n ( a n + 1 ) of the Banach limit in (3.13), we obtain

LIM n ( ( A I ) x t , x t x n ) = LIM n ( ( A I ) x t , x t x n + 1 ) θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + 1 2 θ t [ LIM n ( x t x n 2 ) LIM n ( x t x n + 1 2 ) ] + S x t x t LIM n ( x t x n ) + t γ V x t μ F S x t LIM n ( x t x n ) + LIM n ( A ( x t x n + 1 ) , x t x n + 1 ) LIM n ( A ( x t x n ) , x t x n ) = θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + S x t x t LIM n ( x t x n ) + t γ V x t μ F S x t LIM n ( x t x n ) .
(3.14)

Since

θ t A ( x t x n ) , x t x n θ t A x t x n 2 θ t K 0 ( as  t 0 ) ,
(3.15)

where A x t x n 2 K,

S x t x t 0,andtγV x t μFS x t 0(as t0),
(3.16)

we conclude from (3.14)-(3.16) that

LIM n ( ( A I ) x ˜ , x ˜ x n ) lim sup t 0 LIM n ( ( A I ) x t , x t x n ) lim sup t 0 θ t γ ¯ 2 LIM n ( A ( x t x n ) , x t x n ) + lim sup t 0 S x t x t LIM n ( x t x n ) + lim sup t 0 t γ V x t μ F S x t LIM n ( x t x n ) = 0 .

This completes the proof. □

Now, using Theorem 3.2, we establish strong convergence of the sequence { x n } generated by the general composite explicit scheme (3.3) to a fixed point x ˜ of T, which is also the unique solution of the variational inequality (3.2).

Theorem 3.3 Let { x n } be the sequence generated by the explicit scheme (3.3), where { α n } and { β n } satisfy the following conditions:

(C1) { α n }[0,1] and { β n }(0,1], α n 0 and β n 0 as n;

(C2) n = 0 β n =.

If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Proof First, note that from the condition (C1), without loss of generality, we assume that α n τ<1 and 2 β n ( γ ¯ 1 ) 1 β n <1 for all n0.

Let x t be defined by (3.8), that is,

x t =(I θ t A)S x t + θ t [ S x t t ( μ F ( S x t ) γ V x t ) ]

for t(0,min{1, 2 γ ¯ τ γ l }), where Sx=λx+(1λ)Tx for 0kλ<1, and lim t 0 x t := x ˜ Fix(S)=Fix(T) (by using Theorem 3.1 and Lemma 2.5(iii)). Then x ˜ is the unique solution of the variational inequality (3.2).

We divide the proof into several steps as follows.

Step 1. We see that

x n pmax { x 0 p , γ V p μ F p + I A p γ ¯ 1 } ,n0,

for all pFix(T) as in the proof of Theorem 3.2. Hence { x n } is bounded and so are {T x n }, { T n x n }, {F T n x n }, {V x n }, and { y n }.

Step 2. We show that lim sup n (IA) x ˜ , x n x ˜ 0. To this end, put

a n := ( A I ) x ˜ , x ˜ x n ,n0.

Then Theorem 3.2 implies that LIM n ( a n )0 for any Banach limit LIM. Since { x n } is bounded, there exists a subsequence { x n j } of { x n } such that

lim sup n ( a n + 1 a n )= lim j ( a n j + 1 a n j )

and x n j vH. This implies that x n j + 1 v since { x n } is weakly asymptotically regular. Therefore, we have

w lim j ( x ˜ x n j + 1 )=w lim j ( x ˜ x n j )=( x ˜ v),

and so

lim sup n ( a n + 1 a n )= lim j ( A I ) x ˜ , ( x ˜ x n j + 1 ) ( x ˜ x n j ) =0.

Then Lemma 2.2 implies that lim sup n a n 0, that is,

lim sup n ( I A ) x ˜ , x n x ˜ = lim sup n ( A I ) x ˜ , x ˜ x n 0.

Step 3. We show that lim n x n x ˜ =0. By using (3.3) and T n x ˜ = x ˜ , we have

y n x ˜ =(I α n μF) T n x n (I α n μF) T n x ˜ + α n (γV x n μF x ˜ ),

and

x n + 1 x ˜ =(I β n A)( T n x n T n x ˜ )+ β n ( y n x ˜ )+ β n (IA) x ˜ .

Applying Lemma 2.1, Lemma 2.6 and Lemma 2.7, we obtain

y n x ˜ 2 = ( I μ α n F ) T n x n ( I μ α n F ) T n x ˜ + α n ( γ V x n μ F x ˜ ) 2 ( I μ α n F ) T n x n ( I μ α n F ) T n x ˜ 2 + 2 α n γ V x n μ F x ˜ , y n x ˜ ( 1 α n τ ) 2 x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ ,

and hence

x n + 1 x ˜ 2 = ( I β n A ) ( T n x n T n x ˜ ) + β n ( y n x ˜ ) + β n ( I A ) x ˜ 2 ( I β n A ) ( T n x n T n x ˜ ) 2 + 2 β n y n x ˜ , x n + 1 x ˜ + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + 2 β n y n x ˜ x n + 1 x ˜ + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + β n ( y n x ˜ 2 + x n + 1 x ˜ 2 ) + 2 β n ( I A ) x ˜ , x n + 1 x ˜ ( 1 β n γ ¯ ) 2 x n x ˜ 2 + β n [ x n x ˜ 2 + 2 α n γ V x n μ F x ˜ y n x ˜ ] + β n x n + 1 x ˜ 2 + 2 β n ( I A ) x ˜ , x n + 1 x ˜ = [ ( 1 β n γ ¯ ) 2 + β n ] x n x ˜ 2 + 2 α n β n γ V x n μ F x ˜ y n x ˜ + β n x n + 1 x ˜ 2 + 2 β n ( I A ) x ˜ , x n + 1 x ˜ .
(3.17)

It then follows from (3.17) that

x n + 1 x ˜ 2 ( 1 β n γ ¯ ) 2 + β n 1 β n x n x ˜ 2 + β n 1 β n [ 2 α n γ V x n μ F x ˜ y n x ˜ + 2 ( I A ) x ˜ , x n + 1 x ˜ ] = ( 1 2 β n ( γ ¯ 1 ) 1 β n ) x n x ˜ 2 + 2 β n ( γ ¯ 1 ) 1 β n 1 2 ( γ ¯ 1 ) [ 2 α n γ V x n μ F x ˜ y n x ˜ + β n γ ¯ 2 x n x ˜ 2 + 2 ( I A ) x ˜ , x n + 1 x ˜ ] = ( 1 ω n ) x n x ˜ 2 + ω n δ n ,

where

ω n = 2 β n ( γ ¯ 1 ) 1 β n and δ n = 1 2 ( γ ¯ 1 ) [ 2 α n γ V x n μ F x ˜ y n x ˜ + β n γ ¯ 2 x n x ˜ 2 + 2 ( I A ) x ˜ , x n + 1 x ˜ ] .

It can easily be seen from Step 2 and conditions (C1) and (C2) that ω n 0, n = 0 ω n = and lim sup n δ n 0. From Lemma 2.3 with r n =0, we conclude that lim n x n x ˜ =0. This completes the proof. □

Corollary 3.2 Let { x n } be the sequence generated by the explicit scheme (3.3). Assume that the sequence { α n } and { β n } satisfy the conditions (C1) and (C2) in Theorem  3.3. If { x n } is asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Putting μ=1, F=I and γ=1 in Theorem 3.3, we obtain the following.

Corollary 3.3 Let { x n } be generated by the following iterative scheme:

{ y n = α n V x n + ( 1 α n ) T n x n , x n + 1 = ( I β n A ) T n x n + β n y n , n 0 .

Assume that the sequence { α n } and { β n } satisfy the conditions (C1) and (C2) in Theorem  3.3. If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Putting α n =0, n0 in Corollary 3.3, we get the following.

Corollary 3.4 Let { x n } be generated by the following iterative scheme:

x n + 1 =(I β n A) T n x n + β n T n x n ,n0.

Assume that the sequence { β n } satisfies the conditions (C1) and (C2) in Theorem  3.3 with α n =0, n0. If { x n } is weakly asymptotically regular, then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Remark 3.1 If { α n }, { β n } in Corollary 3.2 and { λ n } in T n satisfy conditions (C2) and

(C3) n = 0 | α n + 1 α n |< and n = 0 | β n + 1 β n |<; or

(C4) n = 0 | α n + 1 α n |< and lim n β n β n + 1 =1 or, equivalently, lim n α n α n + 1 α n + 1 =0 and lim n β n β n + 1 β n + 1 =0; or,

(C5) n = 0 | α n + 1 α n |< and | β n + 1 β n |o( β n + 1 )+ σ n , n = 0 σ n < (the perturbed control condition);

(C6) n = 0 | λ n + 1 λ n |<,

then the sequence { x n } generated by (3.3) is asymptotically regular. Now we give only the proof in the case when { α n }, { β n }, and { λ n } satisfy the conditions (C2), (C5), and (C6). By Step 1 in the proof of Theorem 3.3, there exists a constant M>0 such that, for all n0,

x n T x n M,μF T n x n +γV x n M,andA T n x n + y n M.

Next, we notice that

T n x n T n 1 x n 1 T n x n T n x n 1 + T n x n 1 T n 1 x n 1 x n x n 1 + | λ n λ n 1 | x n 1 T x n 1 x n x n 1 + | λ n λ n 1 | M .

So we obtain, for all n0,

y n y n 1 = α n γ ( V x n V x n 1 ) + γ ( α n α n 1 ) V x n 1 + ( I α n μ F ) T n x n ( I α n μ F ) T n 1 x n 1 + μ ( α n α n 1 ) F T n 1 x n 1 ( 1 α n ( τ γ l ) ) T n x n T n 1 x n 1 + | α n α n 1 | ( γ V x n 1 + μ F T n 1 x n 1 ) ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + | α n α n 1 | M ,

and hence

x n + 1 x n = ( I β n A ) T n x n + β n y n ( I β n 1 A ) T n 1 x n 1 β n 1 y n 1 ( I β n A ) ( T n x n T n 1 x n 1 ) + | β n β n 1 | A T n 1 x n 1 + β n y n y n 1 + | β n β n 1 | y n 1 ( 1 β n γ ¯ ) T n x n T n 1 x n 1 + β n ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + β n | α n α n 1 | M + | β n β n 1 | ( A T n 1 x n 1 + y n 1 ) ( 1 β n γ ¯ ) ( x n x n 1 + | λ n λ n 1 | M ) + β n [ ( 1 α n ( τ γ l ) ) ( x n x n 1 + | λ n λ n 1 | M ) + | α n α n 1 | M ] + | β n β n 1 | M ( 1 β n γ ¯ ) x n x n 1 + | λ n λ n 1 | M + β n x n x n 1 + | λ n λ n 1 | M + | α n α n 1 | M + | β n β n 1 | M = ( 1 β n ( γ ¯ 1 ) ) x n x n 1 + | β n β n 1 | M + 2 | λ n λ n 1 | M + | α n α n 1 | M ( 1 β n ( γ ¯ 1 ) ) x n x n 1 + ( o ( β n ) + σ n 1 ) M + | α n α n 1 | M + 2 | λ n λ n 1 | M .
(3.18)

By taking s n + 1 = x n + 1 x n , ω n = β n ( γ ¯ 1), ω n δ n =Mo( β n ) and r n =(| α n α n 1 |+ σ n 1 +2| λ n λ n 1 |)M, from (3.18) we have

s n + 1 (1 ω n ) s n + ω n δ n + r n .

Hence, by the conditions (C2), (C5), (C6), and Lemma 2.3, we obtain

lim n x n + 1 x n =0.

In view of this observation, we have the following.

Corollary 3.5 Let { x n } be the sequence generated by the explicit scheme (3.3), where the sequences { α n }, { β n }, and { λ n } satisfy the conditions (C1), (C2), (C5), and (C6) (or the conditions (C1), (C2), (C3) and (C6), or the conditions (C1), (C2), (C4), and (C6)). Then { x n } converges strongly to x ˜ Fix(T), which is the unique solution of the variational inequality (3.2).

Remark 3.2 (1) Our results improve and extend the corresponding results of Ceng et al. [18] in the following respects:

  1. (a)

    The nonexpansive map** S:HH in [18] is extended to the case of a k-strictly pseudocontractive map** T:HH.

  2. (b)

    The contractive map** f in [18] with constant α(0,1) is extended to the case of a Lipschitzian map** V with constant l0.

  3. (c)

    The range 0<γα<τ=μ(η μ ρ 2 2 ) in [18] is extended to the case of range 0<γl<τ=1 1 μ ( 2 η μ ρ 2 ) . (For this fact, see Remark 3.1 of [17].)

(2) We point out that the condition (C3) n = 0 | α n + 1 α n |< and n = 0 | β n + 1 β n |< in [[18], Theorem 3.2] is relaxed to the case of the weak asymptotic regularity on { x n } in Theorem 3.3.

(3) The condition (C5) on { β n } in Corollary 3.5 is independent of condition (C3) or (C4) in Remark 3.1, which was imposed in Theorem 3.2 of Ceng et al. [18]. For this fact, see [24, 25].

(4) Our results also complement and develop the corresponding ones given by Cho et al. [5] and Jung [68] for the strictly pseudocontractive map** as well as Yamada [12], Marino and Xu [13], Tian [15] and Ceng et al. [17] for the nonexpansive map**.

(5) For several iterative schemes based on hybrid steepest-descent method for generalized mixed equilibrium problems, variational inequality problems, and fixed point problems for strictly pseudocontractive map**s, we can also refer to [2632] and the references therein.