Anti-plane Shear in Hyperelasticity

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Variational Views in Mechanics

Part of the book series: Advances in Mechanics and Mathematics ((ACM,volume 46))

Abstract

We reconsider anti-plane shear deformations of the form φ(x) = (x 1 , x 2 , x 3 + u(x 1, x 2)) based on prior work of Knowles and relate the existence of anti-plane shear deformations to fundamental constitutive concepts of elasticity theory like polyconvexity, rank-one convexity, and tension-compression symmetry. In addition, we provide finite element simulations to visualize our theoretical findings.

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Notes

  1. 1.

    Possible boundary conditions are Dirichlet or Neumann boundary conditions which permit an APS-deformation of the surface  Ω of Ω. Here, we restrict our attention to Dirichlet boundary condition for simplicity of exposition.

  2. 2.

    The solutions of the Euler-Lagrange equations are the stationary points of the original minimization problem and for the most part impossible to solve analytically.

  3. 3.

    For the homogeneous deformation u(x 1, x 2) = c 1 x 1 + c 2 x 2 + c 3 with constants \(c_1,c_2,c_3\in \mathbb {R}\,,\) it follows directly from the linearity of u that \(\alpha =u_{,x_1}=c_1\) and \(\beta =u_{,x_2}=c_2\,.\) This implies I 1 = I 2 = 3 + α 2 + β 2 = const., which shows that G(I 1, I 2) , H(I 1, I 2) , p(I 1, I 2) , q(I 1, I 2) =  const. Thus, all three Euler-Lagrange equations are trivially fulfilled.

  4. 4.

    Convexity is clearly not necessary for the existence of a minimizer, see, e.g., [16], but it will turn out later that this convexity condition is not a particularly limiting property for most elastic energy functions.

  5. 5.

    For the necessity of (K1), see Knowles [25, eq.(3.22)].

  6. 6.

    With the notation from (10), we can restate (K1) as b H(I 1, I 2) = G(I 1, I 2) with constant \(b\in \mathbb {R}\). Therefore, the relationship together with b H(I 1, I 2) = G(I 1, I 2) yields

  7. 7.

    Note again that I 1 = I 2 = 3 + γ 2 = 3 + ∥∇u2.

  8. 8.

    For detailed calculations, see [43].

  9. 9.

    Gao [12]:“ […] the equilibrium equation […] has just one non-trivial component [namely equation (III)].” Gao claims that Knowles’ condition (K1) is automatically satisfied for every elastic energy function with b = 0, which is clearly not the case (Table 1).

  10. 10.

    For APS-deformations, I 1 = I 2 = 3 + ∥∇u2 and I 3 = 1.

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Acknowledgment

We thank Giuseppe Saccomandi (University of Perugia) and Roger Fosdick (University of Minnesota) for helpful discussions.

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Correspondence to Patrizio Neff .

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Appendix

Appendix

Recall that in the isotropic case, the Cauchy-stress tensor can always be expressed in the form

(36)

with scalar-valued functions β i depending on the invariants of B. In the hyperelastic isotropic case, β 0, β 1, and β −1 are given by

$$\displaystyle \begin{aligned} \beta_0=\frac{2}{\sqrt{I_3}}\left(I_2\hspace{0.07em}\frac{\partial W}{\partial I_2}+I_3\hspace{0.07em}\frac{\partial W}{\partial I_3}\right),\quad \beta_1=\frac{2}{\sqrt{I_3}}\hspace{0.07em}\frac{\partial W}{\partial I_1},\quad \beta_{-1}=-2\sqrt{I_3}\hspace{0.07em}\frac{\partial W}{\partial I_2}.{} \end{aligned} $$
(37)

Lemma 8

Let \(\varphi \colon \Omega \to \mathbb {R}\) , φ(x) = (x 1 + γ x 2, x 2, x 3) be a simple shear deformation, with \(\gamma \in \mathbb {R}\) denoting the amount of shear. Then the Cauchy shear stress σ 12 of an arbitrary isotropic energy function W(I 1, I 2, I 3) is monotone as a scalar-valued function depending on the amount of shear for positive γ if and only if W is APS-convex.

Proof

We consider the Cauchy-stress tensor for an arbitrary material which is stress-free in the reference configuration:

(38)

In the case of simple shear we compute [6, p.41]

(39)
(40)

Therefore, the Cauchy shear stress component σ 12 is a scalar-valued function depending on the amount of shear γ, given by

(41)

The positivity of the Cauchy shear stress is already implied by the (weak) empirical inequalities β 1 > 0 , β −1 ≤ 0. The condition for shear-monotonicity is given by

(42)

which is equivalent to APS-convexity condition (APS2) of the energy function W(I 1, I 2, I 3) . □

Remark 11

The empirical inequalities (27) state that β 0 ≤ 0 , β 1 > 0 , β −1 ≤ 0. In the case of APS-deformations (I 1 = I 2 = 3 + γ 2 , I 3 = 1), Pucci et al. [38, eq.(4.3)] obtain the inequality

(43)

where p, q are real numbers such that p > 0 and q ≠ 0”, by a “simple manipulation of the empirical inequalities (27) and [the stress-free reference configuration]”. In [38, Remark III], it is pointed out correctly that in the case of \(p=1\,,q^2=\frac {1}{2}\) (they erroneously use q = 1) the resulting constitutive inequality

$$\displaystyle \begin{aligned} 0&<2\left((I_1-3)\hspace{0.07em}(h^*)'(3+\gamma^2)+\frac{1}{2}\hspace{0.07em}h^*(3+\gamma^2)\right)\\ &=(h^*)'(3+\gamma^2)\cdot 2\hspace{0.07em}\gamma^2+h^*(3+\gamma^2)=\frac{\mathrm{d}}{\mathrm{d}\gamma}\left[\gamma\hspace{0.07em}h^*(3+\gamma^2)\right] \end{aligned} $$
(44)

is equivalent to APS-convexity by Eq. (APS3) with

(45)

We are, however, not able to reproduce a proof of inequality (43), see also the counterexample in Remark 9.

Lemma 9

Let W be a sufficiently smooth isotropic energy function such that the induced Cauchy-stress response satisfies the (weak) empirical inequalities. Then for sufficiently small shear deformations (i.e., within a neighborhood of the identity ), the Cauchy shear stress is a monotone function of the amount of shear.

Proof

In Lemma 8, we already computed the Cauchy shear stress corresponding to a simple shear to be σ 12(γ) = (β 1 − β −1) γ, with \(\gamma \in \mathbb {R}\) denoting the amount of shear. The monotonicity of this map** is equivalent to

$$\displaystyle \begin{aligned} 0&<\frac{\mathrm{d}}{\mathrm{d}\gamma}\sigma_{12}(\gamma)=\frac{\mathrm{d}}{\mathrm{d}\gamma}\left[(\beta_1(3+\gamma^2)-\beta_{-1}(3+\gamma^2))\hspace{0.07em}\gamma\right]\\ &=\left(\beta_1^{\prime}(3+\gamma^2)-\beta_{-1}^{\prime}(3+\gamma^2)\right)2\hspace{0.07em}\gamma^2+\beta_1(3+\gamma^2)-\beta_{-1}(3+\gamma^2)\,. \end{aligned} $$
(46)

According to the (weak) empirical inequalities, β 1(3) − β −1(3)=: μ > 0. Therefore, β 1(3 + γ 2) − β −1(3 + γ 2) ≥ ε > 0 for sufficiently small \(\gamma \in \mathbb {R}\). If W and thus β 1, β −1 are sufficiently smooth, then \(\beta _1^{\prime }-\beta _2^{\prime }\) is locally Lipschitz-continuous, and thus within a compact neighborhood of ,

for every sufficiently small shear deformation, i.e., sufficiently small γ. □

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Voss, J., Baaser, H., Martin, R.J., Neff, P. (2021). Anti-plane Shear in Hyperelasticity. In: Mariano, P.M. (eds) Variational Views in Mechanics. Advances in Mechanics and Mathematics(), vol 46. Birkhäuser, Cham. https://doi.org/10.1007/978-3-030-90051-9_10

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